screwdriver
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[FONT="]Small personal grow cabinet[/FONT]
[FONT="]The dimensions of the whole cabinet are 18 wide by 18 deep by 85 in height. The left side of the cabinet is located against a concrete basement wall cavity (not shown). This is the coolest place to draw air for the cabinet. I used the wall cavity on the right side for an air duct. This makes it simple to achieve proper air control for all three sections.[/FONT]
[FONT="]The green section on top is the vegetative chamber and is 31 in height. By multiplying width, depth and height we get 10044 cubic inches. By dividing by 1728 we can convert to cubic feet, 5.8 cuft in vegetative chamber. The red section in the middle is 10 in height and used to hold the ballast for the hps light, timers and a heat sink used to help remove heat from the flowering chamber. The last section, which is orange, is the flowering chamber and is 44 in height. Again, multiplying width, depth and height we get 14256 cubic inches and convert that to 8.25 cubic feet. I painted the interior a flat white then decided to use the rest of some mylar. I ran out so I just tried to cover the most area I could.[/FONT]
View attachment 1.jpg
[FONT="]The vegetative chamber has a 100 watt metal halide security light from a home supply store. The light was disassembled and the ballast section was placed on the ceiling of the chamber where the heat from the unit would be furthest away from the plants. The light was placed into a bake-a-round that I cut in half. Then flexible foil dryer duct was used on each end to connect to the air ducting. This is because the light needed to be raised and lowered depending on the size of the plant. I added a small 12 vdc computer fan for a little air movement inside the box.[/FONT]
View attachment 2.jpg
[FONT="]The flowering chamber has a standard 250 watt hps light mounted in a bake-a-round that is ridged mounted to the air ducts. Therefore, the plants must be raised and lowered on a set of shelves mounted on the back wall of chamber. This light generates a lot of heat and is mounted as high as possible and the light reflector mounts to the top of the cabinet and extends into the center section where heat sinks from some salvaged computer processors helps to remove the heat. Again, adding a small computer fan for air movement.[/FONT]
View attachment 3.jpg
[FONT="]This is the center section holding some equipment. It is also where I installed the 15 amp dedicated circuit for the cabinet. The door is sealed with weather stripping and caulk is used to seal the interior.[/FONT]
[FONT="]Air flow theory[/FONT]
[FONT="]I figure that if a fan that attaches to a 4 duct is pulling air from multiple locations. As long as the sum of the ducts cross sectional area is close to sum of the cross sectional area of the attached ducts, it should pull air proportionally from the ducts, but I can only pull the cfm that the fan can pull. Im sure there may be other factors but thats what Im going on.[/FONT]
View attachment 4.jpg
[FONT="]There is a 123 cfm can fan for a 4 duct used as the exhaust. This pulls air at a constant level thru the cavity in the wall. Before putting the drywall in the interior of the cabinet I sealed all the cracks with latex caulk to prevent as much air leakage as possible. Each of the 5 holes in the duct will draw a percentage of the total air flow of fan. There are three 1 3/4 holes and two 3 3/4 holes on the right side duct. The two larger holes sizes are not used except with an extra calculation because there are restrictions within those which is the diameter of the light bulbs. The air inlets in each of the sections are also 1 3/4" as well as 3 3/4" for the larger holes. Remember, heat rises so the air inlets are all low for bringing cool air into cabinet and the air outlets are all at the highest point to remove the rising heat. The doors on each section are fitted and sealed using weather stripping to minimize air and light leakage.[/FONT]
[FONT="]Calculations [/FONT][FONT="](math required)[/FONT]
[FONT="]The first formula needed is for finding the area of a circle, pi(3.14) times r(radius) squared. So for the smaller holes it would be 3.14*(.875*.875) which equals 2.4 square inches. Remember, the larger holes have the extra calculations. The diameter of the metal halide bulb used is 2. That area will need to be subtracted from the area of the cool tube. That is the most restrictive portion of that duct. So the area of the bulb is .I did this in my head without a calculator. I hope you can do the same whether stoned or not. The answer is 3.14 square inches. The cool tube inner diameter is 3 1/2. There is also about 1 square inch of a metal bracket holding the bulb in place that is part of the restriction. The area for the cool tube is, 3.14*(1.75*1.75) which equals 9.6 square inches. This figure needs the bulb and bracket area subtracted from it, 9.6-3.14-1 which is 5.5 square inches. Again, the most restrictive section in the duct, the hps light bulb has a diameter of 1 3/4". Again, we dont need the calculator because we all ready have done that size. What a coincidence. When I was stoned I thought the heavens aligned for me but in thinking back it probably isnt a big deal. Anyway, the area we are looking for is 9.6-2.4 which is 7.2 square inches. Some copper wire holds that in place and that was too small for me to worry about.[/FONT]
[FONT="]The area in which the total air path flows through is 7.2 (the three 2.4numbers) plus 5.5(veg light) plus 7.2(flower light) which totals 19.9 square inches.[/FONT]
[FONT="]When does all this math stop?[/FONT]
[FONT="]So, if we setup this up like a ratio. Most of the air flow will pass over the hps bulb then the mh bulb and the rest is divided among the three small holes for the cabinets. For the hps bulb the calculation is 7.2/19.9(the total area) which is 36% of the air flow. Mh bulb is 5.5/19.9 which is 28% and the smaller holes would be 2.4/19.9= 12% each. [/FONT]
[FONT="] So, the last of the math.[/FONT]
[FONT="]The total cfm of the fan I used is 123, the hps should have 36% of the total cfm, 123/.36, which is 44 cfm to cool the 250 watt light. 28% of the total, 123/.28, which is 34 cfm to cool the 100 watt mh and 15 cfm for each of the smaller holes.[/FONT]
[FONT="]
[/FONT]
[FONT="]The dimensions of the whole cabinet are 18 wide by 18 deep by 85 in height. The left side of the cabinet is located against a concrete basement wall cavity (not shown). This is the coolest place to draw air for the cabinet. I used the wall cavity on the right side for an air duct. This makes it simple to achieve proper air control for all three sections.[/FONT]
[FONT="]The green section on top is the vegetative chamber and is 31 in height. By multiplying width, depth and height we get 10044 cubic inches. By dividing by 1728 we can convert to cubic feet, 5.8 cuft in vegetative chamber. The red section in the middle is 10 in height and used to hold the ballast for the hps light, timers and a heat sink used to help remove heat from the flowering chamber. The last section, which is orange, is the flowering chamber and is 44 in height. Again, multiplying width, depth and height we get 14256 cubic inches and convert that to 8.25 cubic feet. I painted the interior a flat white then decided to use the rest of some mylar. I ran out so I just tried to cover the most area I could.[/FONT]
View attachment 1.jpg
[FONT="]The vegetative chamber has a 100 watt metal halide security light from a home supply store. The light was disassembled and the ballast section was placed on the ceiling of the chamber where the heat from the unit would be furthest away from the plants. The light was placed into a bake-a-round that I cut in half. Then flexible foil dryer duct was used on each end to connect to the air ducting. This is because the light needed to be raised and lowered depending on the size of the plant. I added a small 12 vdc computer fan for a little air movement inside the box.[/FONT]
View attachment 2.jpg
[FONT="]The flowering chamber has a standard 250 watt hps light mounted in a bake-a-round that is ridged mounted to the air ducts. Therefore, the plants must be raised and lowered on a set of shelves mounted on the back wall of chamber. This light generates a lot of heat and is mounted as high as possible and the light reflector mounts to the top of the cabinet and extends into the center section where heat sinks from some salvaged computer processors helps to remove the heat. Again, adding a small computer fan for air movement.[/FONT]
View attachment 3.jpg
[FONT="]This is the center section holding some equipment. It is also where I installed the 15 amp dedicated circuit for the cabinet. The door is sealed with weather stripping and caulk is used to seal the interior.[/FONT]
[FONT="]Air flow theory[/FONT]
[FONT="]I figure that if a fan that attaches to a 4 duct is pulling air from multiple locations. As long as the sum of the ducts cross sectional area is close to sum of the cross sectional area of the attached ducts, it should pull air proportionally from the ducts, but I can only pull the cfm that the fan can pull. Im sure there may be other factors but thats what Im going on.[/FONT]
View attachment 4.jpg
[FONT="]There is a 123 cfm can fan for a 4 duct used as the exhaust. This pulls air at a constant level thru the cavity in the wall. Before putting the drywall in the interior of the cabinet I sealed all the cracks with latex caulk to prevent as much air leakage as possible. Each of the 5 holes in the duct will draw a percentage of the total air flow of fan. There are three 1 3/4 holes and two 3 3/4 holes on the right side duct. The two larger holes sizes are not used except with an extra calculation because there are restrictions within those which is the diameter of the light bulbs. The air inlets in each of the sections are also 1 3/4" as well as 3 3/4" for the larger holes. Remember, heat rises so the air inlets are all low for bringing cool air into cabinet and the air outlets are all at the highest point to remove the rising heat. The doors on each section are fitted and sealed using weather stripping to minimize air and light leakage.[/FONT]
[FONT="]Calculations [/FONT][FONT="](math required)[/FONT]
[FONT="]The first formula needed is for finding the area of a circle, pi(3.14) times r(radius) squared. So for the smaller holes it would be 3.14*(.875*.875) which equals 2.4 square inches. Remember, the larger holes have the extra calculations. The diameter of the metal halide bulb used is 2. That area will need to be subtracted from the area of the cool tube. That is the most restrictive portion of that duct. So the area of the bulb is .I did this in my head without a calculator. I hope you can do the same whether stoned or not. The answer is 3.14 square inches. The cool tube inner diameter is 3 1/2. There is also about 1 square inch of a metal bracket holding the bulb in place that is part of the restriction. The area for the cool tube is, 3.14*(1.75*1.75) which equals 9.6 square inches. This figure needs the bulb and bracket area subtracted from it, 9.6-3.14-1 which is 5.5 square inches. Again, the most restrictive section in the duct, the hps light bulb has a diameter of 1 3/4". Again, we dont need the calculator because we all ready have done that size. What a coincidence. When I was stoned I thought the heavens aligned for me but in thinking back it probably isnt a big deal. Anyway, the area we are looking for is 9.6-2.4 which is 7.2 square inches. Some copper wire holds that in place and that was too small for me to worry about.[/FONT]
[FONT="]The area in which the total air path flows through is 7.2 (the three 2.4numbers) plus 5.5(veg light) plus 7.2(flower light) which totals 19.9 square inches.[/FONT]
[FONT="]When does all this math stop?[/FONT]
[FONT="]So, if we setup this up like a ratio. Most of the air flow will pass over the hps bulb then the mh bulb and the rest is divided among the three small holes for the cabinets. For the hps bulb the calculation is 7.2/19.9(the total area) which is 36% of the air flow. Mh bulb is 5.5/19.9 which is 28% and the smaller holes would be 2.4/19.9= 12% each. [/FONT]
[FONT="] So, the last of the math.[/FONT]
[FONT="]The total cfm of the fan I used is 123, the hps should have 36% of the total cfm, 123/.36, which is 44 cfm to cool the 250 watt light. 28% of the total, 123/.28, which is 34 cfm to cool the 100 watt mh and 15 cfm for each of the smaller holes.[/FONT]
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