W
woodydude
Guest
Hi
I am moving my grow room around.
At present, I have 2 fans. A 5" 280m3/h(165cfm) and a 6" 715m3/h(420cfm).
Eventually, I will be using the small 5" fan as an intake fan, for now though, I will have to have a passive intake.
I have 2 cool tubes housing 600w lights.
I have a carbon filter.
The room size will be 4' x 8' x 8'
My plan is to draw air for the lights from the crawl space under the room and exhause out through the crawl space above the room and into the attic via a 10" duct I have.
The other fan will be drawing air from the room, through the carbon filter and exhausting into the same 10 duct as above.
My problem is which fan to use for the lights and which to use for the room.
I am not certain the 5" fan will be powerful enough to cool the lights.
At present, the 5" is used as an intake fan, the 6" is connected to both lights and carbon filter so is using the room air to cool the lights.
I am scratching my head trying to work out which to use for which.
Does anyone know of a calculation that may help. I only want to do the job once! Lol
Thanks
W
I am moving my grow room around.
At present, I have 2 fans. A 5" 280m3/h(165cfm) and a 6" 715m3/h(420cfm).
Eventually, I will be using the small 5" fan as an intake fan, for now though, I will have to have a passive intake.
I have 2 cool tubes housing 600w lights.
I have a carbon filter.
The room size will be 4' x 8' x 8'
My plan is to draw air for the lights from the crawl space under the room and exhause out through the crawl space above the room and into the attic via a 10" duct I have.
The other fan will be drawing air from the room, through the carbon filter and exhausting into the same 10 duct as above.
My problem is which fan to use for the lights and which to use for the room.
I am not certain the 5" fan will be powerful enough to cool the lights.
At present, the 5" is used as an intake fan, the 6" is connected to both lights and carbon filter so is using the room air to cool the lights.
I am scratching my head trying to work out which to use for which.
Does anyone know of a calculation that may help. I only want to do the job once! Lol
Thanks
W